Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The specific heat capacity of steel is 450 J/kg°C. If heat is added to 2 kg of steel for 30seconds, raising its temperature from 10°C to 32°C, what is the heat flow rate? Express your answer in W.

Sagot :

Given:

The specific heat capacity of steel is

[tex]c=\text{ 450 J/kg }^{\circ}C[/tex]

The mass of the steel is m = 2 kg

The initial temperature of steel is

[tex]T_i=\text{ 10}^{\circ}\text{ C}[/tex]

The final temperature of steel is

[tex]T_f\text{ = 32}^{\circ}C[/tex]

The time is t = 30 s

To find the heat flow rate.

Explanation:

The heat flow rate can be calculated by the formula

[tex]\frac{Q}{t}=\frac{mc(T_f-T_i)}{t}[/tex]

On substituting the value, the heat flow rate will be

[tex]\begin{gathered} \frac{Q}{t}=\text{ }\frac{2\times450\times(32-10)}{30} \\ =\text{ 660 W} \end{gathered}[/tex]

Thus, the heat flow rate is 660 W.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.