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Sagot :
The number of students given are 24.
The students who play sudoku is,
[tex]\frac{2}{3}\times24=16.[/tex]Out of the students who play sudoku , the students who play chess are
[tex]16\times\frac{3}{8}=6.[/tex]Therefore the students who play sudoku are 16 and play chess are 6.
The number of students who play both chess and sudoku is,
[tex]\text{ n}(C\cup S)=n(C)+n(S)-n(C\cap S)[/tex]Substitute the values,
[tex]24=16+6-n(C\cap S)[/tex][tex]n(C\cap S)=24-22[/tex][tex]n(C\cap S)=2.[/tex]Thus , the number of students who play both chess and sudoku is, 2.
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