Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

How many real solutions does the equation \displaystyle -2x^2-6x+15=2x+5−2x 2 −6x+15=2x+5 have?

How Many Real Solutions Does The Equation Displaystyle 2x26x152x52x 2 6x152x5 Have class=

Sagot :

-2x² - 6x + 15 = 2x +5

Re-arrange the equation

-2x² - 6x -2x+ 15-5=0

-2x² -8x + 10 = 0

Multiply through by negative one

2x² + 8x - 10 =0

Now;

solve by factorization

Find two numbers such that its product give -20x² and its sum gives 8x and 8x by them

That is;

2x² + 10x - 2x - 10 = 0

2x(x+5) -2(x+5) = 0

(2x - 2) (x+5) = 0

Either 2x - 2 = 0

2x = 2

x= 1

Or

x+5 = 0

x=-5

Hence it has 2 real solutions

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.