Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Write an equation in slope-intercept form of the lineO24+2+4161O A y=-7xBy=2x + 7OCy=2x - 7D. Y:-7x + 2

Sagot :

From the graph provided, we will need to find the slope and also coordinates in other to find the equation of the graph.

For the slope,

[tex]m=\frac{y_2-y_1}{x_2-x_{1_{}}_{}}_{}[/tex]

From the graph,

Where x=0, y=0 which can be written in coordinates of (x2, y2) as (0, 0)

Where x=3.5, y=-7 which can be written in coordinates of (x1, y1) as (3.5, -7)

To find the slope,

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-7)}{0-3.5}=\frac{7}{-3.5}=-2_{}[/tex]

The slope of the graph m is -2

The formula for the equation of a graph is,

[tex]\frac{y-y_1}{x-x_1}=m[/tex]

Where (x1, y1) is (3.5, -7),

[tex]\begin{gathered} \frac{y-y_1}{x-x_1}=m \\ \frac{y-(-7)_{}}{x-(3.5)}=-2 \\ \frac{y+7}{x-3.5}=-2 \\ \text{Crossmultiply} \\ y+7=-2(x-3.5) \\ y+7=-2x+7 \\ y=-2x+7-7 \\ y=-2x \end{gathered}[/tex]

Hence, the equation of the graph is deduced above.