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In AFGHFH.GF +40, HF 3x - 20, and GH find the value of 21 20

In AFGHFHGF 40 HF 3x 20 And GH Find The Value Of 21 20 class=

Sagot :

You have the next triangle:

As the triangle has two angles that are congruent, then it is a isisceles triangle. The opposite sides of the equal angles have the same measure.

Sides FG and GH have the same measure:

[tex]FG\cong GH[/tex][tex]x+40=2x+20[/tex]

Use this equation to find the value of x:

- Substract in both sides of the equation 2x:

[tex]\begin{gathered} x-2x+40=2x-2x+20 \\ -x+40=20 \end{gathered}[/tex]

- Substract in both sides of the equation 40:

[tex]\begin{gathered} -x+40-40=20-40 \\ -x=-20 \end{gathered}[/tex]

- Multiply both sides of the equation by -1:

[tex]\begin{gathered} (-1)(-x)=(-1)(-20) \\ \\ x=20 \end{gathered}[/tex]Answer x=20
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