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Sagot :
the equation given was
[tex]\begin{gathered} 9x-12y=-12 \\ -6x+8y=8 \end{gathered}[/tex]now to solve this equation, we should solve the simultaneous equation and get the values of x and y
now, let's take equation 1 and solve for x
[tex]\begin{gathered} 9x-12y=-12 \\ \text{make y the subject of formula} \\ 9x=-12+12y \\ \text{divide both sides by 9} \\ \frac{9x}{9}=\frac{-12+12y}{9} \\ x=\frac{-12+12y}{9} \end{gathered}[/tex]put x into equation 2
[tex]\begin{gathered} -6x+8y=8 \\ x=\frac{-12+12y}{9} \\ \text{put x into the equation} \\ -6(\frac{-12+12y}{9})+8y=8 \\ \frac{72-72y}{9}+8y=8 \\ 8-8y+8y=8 \\ 0=0 \end{gathered}[/tex]from the solution, y = 0
put y = 0 into either equation 1 or 2
from equation 1
[tex]\begin{gathered} 9x-12y=-12 \\ \text{put y = 0} \\ 9x-12(0)=-12 \\ 9x-0=-12 \\ 9x=-12 \\ \text{divide both sides by 9} \\ \frac{9x}{9}=-\frac{12}{9} \\ x=-\frac{4}{3} \end{gathered}[/tex]from the above calculation, the above equation has only one solution.
the ordered pair is
[tex](x,y)=(-\frac{4}{3},0)[/tex]
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