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Solve the following equation for x by using the quadratic formula. If there is more than one solution, enter your solutions as a comma-separated list, like "1, 3".2x^2+9x+7=0

Sagot :

Answer:

Explanation:

Given the equation:

[tex]2x^2+9x+7=0[/tex]

• The coefficient of x², a=2

,

• The coefficient of x, b=9

,

• The constant, c=7

Substitute these values into the quadratic formula:

[tex]\begin{gathered} x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a} \\ \implies x=\dfrac{-9\pm\sqrt[]{9^2-4(2)(7)}}{2\times2}=\dfrac{-9\pm\sqrt[]{81-56}}{4}=\dfrac{-9\pm\sqrt[]{25}}{4} \\ \implies x=\dfrac{-9\pm5}{4} \end{gathered}[/tex]

Thus, the values of x are:

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