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Calculate percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water?

Sagot :

Answer:

25.81%

Explanations:

The formula for calculating the percent volume/volume of a solution is given as:

[tex]\%v\text{/v}.=\frac{volume\text{ of solute}}{volume\text{ of solution}}\times100[/tex]

Given the following parameters

volume of solute (methanol) = 80mL

volume of solution = volume of water + methanol

volume of solution = 80mL + 230mL = 310mL

Determine the required percent v/v

[tex]\begin{gathered} \%v\text{/}v=\frac{80mL}{310mL}\times100 \\ \%v\text{/}v=\frac{800}{31} \\ \%v\text{/}v=25.81\% \end{gathered}[/tex]

Hence the percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water is 25.81%

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