The general equation of an ellipse is:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1.[/tex]
Where:
• (h, k) are the coordinates of the centre,
,
• a and b are the lengths of the legs.
The parts of the ellipse are:
In this case, we have the equation:
[tex]\frac{(x+1)^2}{5^2}+\frac{(y-4)^2}{4^2}=1.[/tex]
So we have:
• (h, k) = (-1, 4),
,
• a = 5,
,
• b = 4.
A) The graph of the ellipse is:
B) The center of the ellipse is (h, k) = (-1, 4).
C) The vertices of the ellipse are:
• (h + a, k) = (-1 + 5, 4) = ,(4, 4),,
,
• (h - a, k) = (-1 - 5, 4) =, (-6, 4),,
D) The endpoints of the minor axis are:
• (h, k + b) = (-1, 4 + 4 ) = ,(-1, 8),,
,
• (h, k - b) = (-1, 4 - 4) = ,(-1, 0),.
E) To find the focuses, we compute c:
[tex]c=\sqrt[]{a^2-b^2}=\sqrt[]{5^2-4^2}=\sqrt[]{25-16}=\sqrt[]{9}=3.[/tex]
The focuses of the ellipse are:
• (h + c, k) = (-1 + 3, 4) = ,(2, 4),,
,
• (h - c, k) = (-1 - 3, 4) = ,(-4, 4),.
Answer
A)
B) (-1, 4)
C) (4, 4), (-6, 4)
D) (-1, 8), (-1, 0)
E) (2, 4), (-4, 4)
