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Layla was hiking in the Grand Canyon with her best friend Saige. The temperature when they started gut was only 4.0° C. She shouted at the canyon wall and 2.8 s later she heard her own voice echoing back. How far away was the canyon wall? a) 4.6 x 10² m b) 46.6 m c) 47 m d) 466.7 m

Layla Was Hiking In The Grand Canyon With Her Best Friend Saige The Temperature When They Started Gut Was Only 40 C She Shouted At The Canyon Wall And 28 S Late class=

Sagot :

Given:

The temperature of the surrounding is 4 degrees Celsius.

The time taken for the echo to reach the ears is t = 2.8 s

Required:

The distance from the canyon wall.

Explanation:

The distance traveled by the sound is 2d as it travels up to the wall and bounces back.

The distance can be calculated by the formula

[tex]d=\frac{v\times t}{2}[/tex]

Here, the speed of sound at 4 degrees Celsius is

[tex]v=331.3\text{ m/s}[/tex]

On substituting the values, the distance traveled will be

[tex]\begin{gathered} d=\frac{331.3\times2.8}{2} \\ =4.6\times10^2\text{ m} \end{gathered}[/tex]

Final Answer: The distance traveled is 4.6 x 10^2 m

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