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What is the mass of 6.02 x 1023 molecules of CO2?

Sagot :

ANSWER

EXPLANATION

Given that

The number o molecules is 6.02 x 10^23 molecules

Firstly, find the number of moles using the below formula

[tex]\text{ mole = }\frac{\text{ number of molecules}}{\text{ Avogadro's number}}[/tex]

Recall, that the Avogadro's number is 6.02 x 10^23

[tex]\begin{gathered} \text{ mole = }\frac{6.02\text{ }\times\text{ 10}^{22}}{6.02\text{ }\times\text{ 10}^{23}} \\ \text{ mole = 1} \end{gathered}[/tex]

Secondly, find the mass of CO2 using the formula below

[tex]\text{ mole = }\frac{mass}{\text{ molar mass}}[/tex]

Recall, that the molar mass of CO2 is given as 44.01 g/mol

[tex]\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ mass = mole }\times\text{ molar mass} \\ \text{ mass = 1 }\times\text{ 44.01} \\ \text{ mass = 44.01 grams} \end{gathered}[/tex]

Therefore, the mass of CO2 is 44 grams