Answered

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The probability of being dealt a club and a diamond is

The Probability Of Being Dealt A Club And A Diamond Is class=

Sagot :

There are a total of 52 cards in a standard deck.

There are 13 club cards and 13 diamond cards.

The probability of getting a club card is given by

[tex]P(club)=\frac{\text{number of club cards}}{\text{total number of cards}}=\frac{13}{52}[/tex]

The probability of getting a diamond card is given by

[tex]P(diamond)=\frac{\text{number of diamond cards}}{\text{total number of cards}}=\frac{13}{52}[/tex]

The probability of getting a club and diamond is given by

"And" means to multiply the probabilites

[tex]\begin{gathered} P(club\; \; and\; \; diamond)=P(club)\times P(diamond) \\ P(club\; \; and\; \; diamond)=\frac{13}{52}\times\frac{13}{52} \\ P(club\; \; and\; \; diamond)=\frac{169}{2704}=\frac{1}{16} \end{gathered}[/tex]

Therefore, the probability of getting a club and diamond is 1/16

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