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what is the y-intercept of the function y=-¹/²cos(3/2x)

Sagot :

Problem

We need to find the y intercept of this function

y=-1/2cos(3/2x)​

Solution

The y intercept correspond to the value of x=0 of the function and we can do this:

y= -1/2 cos (3/2 *0)

y= -1/2 cos (0) = -1/2

And then the best solution it would be:

x=0 and y= -1/2

(0,-1/2)

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