Given the set of data:
11, 7, 14, 2, 8, 13, 3, 6, 10, 3, 8, 4, 8, 4, 7
Let's find the standard deviation.
To find the standard deviation, apply the formula:
[tex]s=\frac{\sqrt{\Sigma(x-\mu)^2}}{n-1}[/tex]
Where:
x is the data
u is the mean
n is the number of data = 15
To find the mean, we have:
[tex]\begin{gathered} mean=\frac{11+7+14+2+8+13+3+6+10+3+8+4+8+4+7}{15} \\ \\ mean=\frac{108}{15} \\ \\ mean=7.2 \end{gathered}[/tex]
Hence, to find the standard deviation, we have:
[tex]\begin{gathered} s=\sqrt{\frac{(11-7.2)^2+(7-7.2)^2+(14-7.2)^2+(2-7.2)^2+(8-7.2)^2+(13-7.2)^2+(3-7.2)^2+(6-7.2)^2+(10-7.2)^2+(3-7.2)^2+(8-7.2)^2+(4-7.2)^2+(8-7.2)^2+(4-7.2)^2+(7-7.2)^2}{15-1}} \\ \\ s=\sqrt{\frac{188.4}{14}} \\ \\ s=\sqrt{13.457} \\ \\ s=3.7 \end{gathered}[/tex]
Therefore, the standard deviation is 3.7
xzANSWER:
3.7
