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Two 4-1 resistors are connected in parallel to a 12-V bat-tery. Use the fact that the voltage across each of the resis-tors is 12 V to find the total current through the battery.What single resistor, if connected to the battery alone(called the equivalent resistance), would draw this samecurrent?

Sagot :

Given data

*The given resistors are

[tex]R_1=R_{2_{}}_{}_{}=4\text{ ohm}[/tex]

*The given battery voltage is V = 12 V

The equivalent resistance in parallel combination is calculated as

[tex]\begin{gathered} R_{eq}=\frac{R_1\times R_2}{R_1+R_2} \\ =\frac{4\times4}{4+4} \\ =\frac{16}{8} \\ =2\text{ ohm} \end{gathered}[/tex]

The total current flows through the battery is calculated as

[tex]\begin{gathered} I=\frac{V}{R_{eq}} \\ =\frac{12}{2} \\ =6\text{ A} \end{gathered}[/tex]

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