Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.Passing through (5,3) with x-intercept 6Write an equation for the line in point-slope form.

Sagot :

In general, the equations of a line in point-slope form and slope-intercept form are:

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y=mx+b \end{gathered}[/tex]

respectively. Where m is the slope of the line, b is a constant, and (x_1, y_1) is a point on the line.

Thus, the point-slope form of the line described by the problem is:

[tex]y-3=m(x-5)[/tex]

We simply need to calculate the slope of the line. For that, we simply require 2 points, we already have (5, 3) and, since the x-intercept is 6, we can deduce that the line goes through (0,6).

Therefore, the slope is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-3}{0-5}=-\frac{3}{5}[/tex]

Then, the solution is:

[tex]y-3=-\frac{3}{5}(x-5)[/tex]

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.