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Sagot :
We have
[tex]\begin{gathered} x+y+z=2 \\ -x+3y+2z=8 \\ 4x+y=4 \end{gathered}[/tex]We have with the third equation
[tex]y=4-4x[/tex]We substitute in the first and second equation
[tex]\begin{gathered} x+4-4x+z=2 \\ -3x+z=-2 \end{gathered}[/tex][tex]\begin{gathered} -x+3(4-4x)+2z=8 \\ -x+12-12x+2z=8 \\ -13x+2z=8-12 \\ -13x+2z=-4 \end{gathered}[/tex]Then we have
[tex]z=-2+3x[/tex]We substitute
[tex]\begin{gathered} -13x+2(-2+3x)=-4 \\ -13x-4-6x=-4 \\ -19x=0 \\ x=0 \end{gathered}[/tex]if x=0
[tex]z=-2[/tex]and if x=0
[tex]y=4[/tex]ANSWER
x=0
y=4
z=-2
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