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How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer: ___________ J (round to the nearest whole number)

Sagot :

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

[tex]W=\Delta K[/tex]

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

[tex]K=\frac{1}{2}mv^2[/tex]

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

[tex]\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\ \\ \therefore K\approx532,346J \end{gathered}[/tex]

Therefore, the answer is: 532,346 J.

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