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What is the area of the figure? Round to the nearest tenth if necessary. Include units in your answer.

What Is The Area Of The Figure Round To The Nearest Tenth If Necessary Include Units In Your Answer class=

Sagot :

We can think of a hexagon in the next way:

This is, a shape made of 6 smaller triangles. So, we only need to calculate the area of one of those triangles and multiply it by 6

There is something interesting, each of the angles of every one of the triangles is 60°, those are equilateral triangles. So, let's focus on one triangle:

Notice that the blue line is the height of the triangle, that's what we need to find it's are using the formula:

[tex]A(triangle)=\frac{hb}{2}[/tex]

So, to calculate the height we use the Pythagoras Theorem

[tex]H^2-O^2=b^2\Rightarrow(20\operatorname{cm})^2-10\operatorname{cm}=b^2\Rightarrow b^2=300\operatorname{cm}\Rightarrow b=10\sqrt[]{3}[/tex]

Finally, the area of one of the triangles is:

[tex]A(triangle)=\frac{1}{2}(20cm)(10\sqrt[]{3}cm)=173.2cm^2[/tex]

And, by multiplying the previous result by 6, we get the area

[tex]A(hexagon)=6\cdot A(triangle)=6(173.2cm^2)=1039.2\operatorname{cm}[/tex]

View image AlyianaS158425
View image AlyianaS158425