The coordinates of the images are;
[tex]undefined[/tex]Here, we want to translate the given triangle
The translation is in the units of (10,2)
What this mean is that we are going to make a translation of 10 in the x-axis direction and 2 units in the y-axis direction
Hence, we are having a unit of 10 rightwards (positive x-axia) and 2 unit of 2 units upwards (vertically on the y-axis)
So what we do now in respective cases is add 10 to the x-axis values of each point and add 2 to the y-axis values of each point
Thus, we have;
[tex]\begin{gathered} A(-1,6)\text{ to A'(-1+10, 6+2)= A'(9,8)} \\ B(0,4)\text{ to B'(0+10, 4+2) = B'(10,6)} \\ C(-6,1)\text{ to C'(-6+10,1+2) = C'(4,3)} \end{gathered}[/tex]