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Factor the polynomial completely.X^2+x+1

Sagot :

[tex]x(x+1)+1[/tex]

1) Examining the expression below, we can group the first and the second term:

[tex]\begin{gathered} x^2+x+1 \\ x(x+1)+1 \\ \end{gathered}[/tex]

Note that there is no way beyond this point. So we could not factor beyond this point.

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