Answered

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I'm having trouble figuring out this problem. Problem: Using the formula below, solve when s = 2.50. A = 6s²

Sagot :

Given the formula:

[tex]A=6s^2[/tex]

Let's solve for A when the value of s is = 2.50

To solve the equation, substitute 2.50 for s and evaluate.

Thus, we have:

[tex]\begin{gathered} A=6(2.50)^2 \\ \end{gathered}[/tex]

Solving further:

[tex]\begin{gathered} A=6(2.50\ast2.50) \\ \\ A=6(6.25)^{} \\ \\ A=6\ast6.25 \\ \\ A=37.5 \end{gathered}[/tex]

Therefore, when the value of s is 2.50, the value of A is 37.5

ANSWER:

37.5

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