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Translate the following into algebraic equation and solve: Twice the sum of a number and five is equal to 40.

Sagot :

Let:

x = Unknown number

Twice the sum of a number and five:

[tex]2(x+5)[/tex]

Is equal to 40:

[tex]2(x+5)=40[/tex]

Solve for x:

Expand the left hand side using distributive property:

[tex]2x+10=40[/tex]

Subtract 10 from both sides:

[tex]2x=30[/tex]

Divide both sides by 2:

[tex]x=15[/tex]