Answered

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write (2 to the power of -1) to the power of 3 with the same base but one exponent

Sagot :

[tex]\frac{1}{8}[/tex]

Explanation

Step 1

[tex](2^{-1})^3[/tex]

remember

[tex]\begin{gathered} a^{-n}=\frac{1}{a^n} \\ (a^n)^m=a^{n\cdot m} \\ (\frac{a}{b})^m=\frac{a^m}{b^m} \end{gathered}[/tex]

Step 2

solve

[tex]\begin{gathered} (2^{-1})^3 \\ (2^{-1})^3=(\frac{1}{2^1})^3=(\frac{1^3}{2^3})=\frac{1}{8} \end{gathered}[/tex]

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