Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

In an electrical circuit with resistors placed in parallel, thereciprocal of the total resistance is equal to the sum of thereciprocals of each resistance:

In An Electrical Circuit With Resistors Placed In Parallel Thereciprocal Of The Total Resistance Is Equal To The Sum Of Thereciprocals Of Each Resistance class=

Sagot :

Answer:

C

[tex]R_2=16.16\Omega[/tex]

Explanation:

Given the below equation;

[tex]\frac{1}{R_c}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]

We're also given;

[tex]\begin{gathered} R_1=25\Omega \\ R_c=10\Omega \end{gathered}[/tex]

Let's substitute the given values into the equation, we'll have;

[tex]\frac{1}{10}=\frac{1}{25}+\frac{1}{R_2}[/tex]

Let's subtract 1/25 from both sides of the equation;

[tex]\begin{gathered} \frac{1}{10}-\frac{1}{25}=\frac{1}{R_2} \\ \frac{5-2}{50}=\frac{1}{R_2} \\ \frac{3}{50}=\frac{1}{R_2} \end{gathered}[/tex]

Let's cross multiply;

[tex]\begin{gathered} 3R_2=50 \\ R_2=\frac{50}{3} \\ R_2=16.16\Omega \end{gathered}[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.