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Sagot :
Part A
Find out the slant height of the cone
Applying the Pythagorean Theorem
AC^2=AB^2+BC^2
we have
AC ----> slant height
AB=4/2=2 in
BC=6 in
substitute given values
AC^2=2^2+6^2
AC^2=40
AC=2√10 in
Part B
Find out the measure of the angle formed between the base and the slant height
we have that
tan( by opposite side divided by adjacent side
tan(mm
Part C
see the figure below to better understand the problem
we have that
AC and DC are slant height
triangle ADC is an isosceles triangle
because AC=DC
that means
mmmmthe answer part C is 36.86 degrees
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