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Sagot :
The given system of equation are :
-6x - y = -16
-6x -5y = -8
On subtracting both the equation we get :
-6x -y -(-6x -5y) = -16 -(-8)
-6x -y +6x +5y = -16 +8
-6x + 6x +5y -y = -8
4y = -8
4y = -8
Divide both side by 4:
4y/4 = -8/4
y = -2
Substitute the value of y =- 2 in the any one equation:
-6x - y = -16
-6x - (-2)= -16
-6x + 2 = -16
-6x = -16 -2
-6x = -18
x = 3
Answer : x = 3, y = -2
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