Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Hi, can you help me to solve this exercise, please!!

Hi Can You Help Me To Solve This Exercise Please class=

Sagot :

Given the Right Triangle BCD, you know that:

[tex]\begin{gathered} BD=8 \\ m\angle BCD=63\degree \end{gathered}[/tex]

Then, you can use the following Trigonometric Function in order to find the length of the side CD:

[tex]\sin \beta=\frac{opposite}{hypotenuse}[/tex]

In this case:

[tex]\begin{gathered} \beta=63\degree \\ opposite=BD=8 \\ hypotenuse=CD \end{gathered}[/tex]

Therefore, substituting values and solving for CD, you get:

[tex]\begin{gathered} \sin (63\degree)=\frac{8}{CD} \\ \\ CD\cdot\sin (63\degree)=8 \end{gathered}[/tex][tex]\begin{gathered} CD=\frac{8}{\sin(63\degree)} \\ \\ CD\approx9.0 \end{gathered}[/tex]

Hence, the answer is:

[tex]CD=9.0[/tex]

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.