Answer:
The compressive stress is 177.93 MN/m²
Explanations:
1 inch = 0.0254 meters
The outside diameter, D = 2.5 in
D = 2.5 x 0.0254
D = 0.0635 m
The inner diameter, d = 1.5 in
d = 1.5 x 0.0254
d = 0.0381 m
The area of circular tube is calculated as:
[tex]\begin{gathered} A\text{ = }\frac{\pi{}}{4}(D^2-d^2) \\ A\text{ = }\frac{3.142}{4}(0.0635^2-0.0381^2) \\ A\text{ = }0.002m^2 \end{gathered}[/tex]
The Area of the circular tube = 0.002 m²
The compressive load = 80 kips
1 kips = 4448.22 N
The compressive load = 4448.22 x 80 N
The compressive load = 355857.6N
[tex]\begin{gathered} \text{Compressive stress = }\frac{Compressive\text{ load}}{\text{Area}} \\ \text{Compressive stress = }\frac{355857.6}{0.002} \\ \text{Compressive stress = }177928800N/m^2 \\ \text{Compressive stress = }177.93MN/m^2 \end{gathered}[/tex]
