Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

How to find the compressive stress in a circular tube

How To Find The Compressive Stress In A Circular Tube class=

Sagot :

Answer:

The compressive stress is 177.93 MN/m²

Explanations:

1 inch = 0.0254 meters

The outside diameter, D = 2.5 in

D = 2.5 x 0.0254

D = 0.0635 m

The inner diameter, d = 1.5 in

d = 1.5 x 0.0254

d = 0.0381 m

The area of circular tube is calculated as:

[tex]\begin{gathered} A\text{ = }\frac{\pi{}}{4}(D^2-d^2) \\ A\text{ = }\frac{3.142}{4}(0.0635^2-0.0381^2) \\ A\text{ = }0.002m^2 \end{gathered}[/tex]

The Area of the circular tube = 0.002 m²

The compressive load = 80 kips

1 kips = 4448.22 N

The compressive load = 4448.22 x 80 N

The compressive load = 355857.6N

[tex]\begin{gathered} \text{Compressive stress = }\frac{Compressive\text{ load}}{\text{Area}} \\ \text{Compressive stress = }\frac{355857.6}{0.002} \\ \text{Compressive stress = }177928800N/m^2 \\ \text{Compressive stress = }177.93MN/m^2 \end{gathered}[/tex]