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Sagot :
Given:
Given the inequalities:4
[tex]\begin{gathered} 4x+3>0 \\ 9x-5<100 \\ x+4\leq10 \\ 72\div x\ge4 \end{gathered}[/tex]Required: Identify the inequality in which x = 8 is a solution.
Explanation:
Substitute 8 for x in each inequality and check whether it satisfies the inequality.
Consider 4x + 3 > 0.
[tex]4\cdot8+3=35>0[/tex]So, x = 8 satisfies the inequality 4x + 3 > 0.
Consider 9x - 5 < 100.
[tex]9\cdot8-5=67<100[/tex]So, x = 8 satisfies the inequality 9x - 5 < 100.
Consider x + 4 ≤ 10.
[tex]8+4=12>10[/tex]So, x = 8 not satisfies the inequality.
Consider 72 ÷ x ≥ 4.
[tex]72\div8=9\ge4[/tex]So, x = 8 satisfies the inequality.
Final Answer: The inequality in which x = 8 is not a solution is x + 4 ≤ 10.
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