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which of the following equations has only one solution? x^2 - 8x + 16 = 0x ( x - 1 ) = 8 x^2 = 16

Sagot :

Simplify the equation x^2 - 8x + 16 = 0 to obtain the value of x.

[tex]\begin{gathered} x^2-8x+16=0 \\ x^2-2\cdot4\cdot x+(4)^2=0 \\ (x-4)^2=0 \\ (x-4)(x-4)=0 \\ x=4 \end{gathered}[/tex]

Equation has one solution, x = 4.

Simplify the equation x ( x - 1 ) = 8 to obtain the value of x.

[tex]\begin{gathered} x(x-1)=8 \\ x^2-x-8=0 \end{gathered}[/tex]

This is a quadratic equation which is not a perfect square so it has two solutions.

Simplify the equation x^2 = 16 to obtain the value of x.

[tex]\begin{gathered} x^2=16 \\ x=\sqrt[]{16} \\ =\pm4 \end{gathered}[/tex]

Thes equation has two solution x = 4 and x = -4.

So equation x^2 - 8x + 16 = 0 has only one solution and remaining equation has two solutions.

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