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Sagot :
Answer:
[tex]x=\frac{9}{16}y^2[/tex]Step-by-step explanation:
Since the vertex of the parabola at the origin (h,k) is (0,0). The standard form of the parabola is represented as:
[tex]\begin{gathered} x=a(y-k)^2+h \\ \end{gathered}[/tex]If the parabola passes through the point (9,-4), we can substitute for (x,y) and (h,k) and solve for ''a.'' and determine the equation:
[tex]\begin{gathered} 9=a(-4-0)^2+0 \\ 9=a(16)+0 \\ a=\frac{9}{16} \\ \end{gathered}[/tex]Then, the equation of the parabola in standard form would be:
[tex]x=\frac{9}{16}y^2[/tex]
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