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Find the equation for the line that passes through the point (-4,1), and that is perpendicular to the line with the equation

Find The Equation For The Line That Passes Through The Point 41 And That Is Perpendicular To The Line With The Equation class=

Sagot :

[tex]y=\frac{4}{3}x+\frac{19}{3}[/tex]

EXPLANATION

Given:

Point ( - 4, 1)

⇒x = -4 and y = 1

Perpendicular equation

3/4 x + y = -5/4

We need to re-write the above equation in the form y = mx + b

y = -3/4 x -5/4

Compare the above with y=mx + b where m is the slope and b is the intercept.

slope(m) = -3/4

Slope of vertical lines are inverse of one another.

This implies that the slpe of our new equation is:

[tex]m=\frac{-1}{m}=\frac{-1}{-\frac{3}{4}}=\frac{4}{3}[/tex]

Next, is to find the intercept of the new equation.

We can find this by substituting m = 4/3 , x = -4 and y = 1 into y=mx + b and then solve for b.

That is;

[tex]\begin{gathered} 1=\frac{4}{3}(-4)+b \\ \\ 1=-\frac{16}{3}+b \\ \\ 1+\frac{16}{3}=b \\ \\ b=\frac{3+16}{3} \\ \\ b=\frac{19}{3} \end{gathered}[/tex]

We can proceed to form the new equation by simply substituting the values of m and b into y=mx + b

Hence, the equation is:

[tex]y=\frac{4}{3}x+\frac{19}{3}[/tex]