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9. You have 500 grams of Cu2S. How many particles are present?

Sagot :

Explanation:

Before we find the number of particles, we have to find the number of moles that are present in 500 g of Cu₂S using the molar mass of it.

molar mass of Cu = 63.55 g/mol

molar mass of S = 32.07 g/mol

molar mass of Cu₂S = 2 * 63.55 g/mol + 1 * 32.07 g/mol

molar mass of Cu₂S = 159.17 g/mol

mass of Cu₂S = 500 g

moles of Cu₂S = 500 g/(159.17 g/mol)

moles of Cu₂S = 3.14 moles

According to Avogadro's Number there are 6.022 *10^23 particles in 1 mol of Cu₂S. Let's use that relationship to find the answer to our problem.

1 mol of Cu₂S = 6.022 * 10^23 particles

number of particles = 3.14 moles * 6.022 *10^23 particles/mol

number of particles = 1.89 *10^24 particles

Answer: There are 1.89 *10^24 particles in 500 g of Cu₂S.