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how do you solve this problem?3 7/3+2 5/6=

Sagot :

Answer:

49/6

Explanation:

In order to add the mixed numbers given, we first convert the mixed numbers to improper fractions.

Now,

[tex]3\frac{7}{3}=3+\frac{7}{3}[/tex]

The number 3 can be rewritten as

[tex]7=3\cdot\frac{3}{3}[/tex]

which helps us rewrite our mixed fraction as

[tex]3+\frac{7}{3}=3\cdot\frac{3}{3}+\frac{7}{3}[/tex][tex]=\frac{9}{3}+\frac{7}{3}[/tex]

adding the numerators gives

[tex]\frac{16}{3}[/tex]

Hence,

[tex]3\frac{7}{3}=\frac{16}{3}[/tex]

Similarly,

[tex]2\frac{5}{6}=2+\frac{5}{6}[/tex]

the number 2 can be rewritten as

[tex]2=2\cdot\frac{6}{6}=\frac{12}{6}[/tex]

therefore, the mixed number becomes

[tex]2+\frac{5}{6}=\frac{12}{6}+\frac{5}{6}[/tex][tex]=\frac{17}{6}[/tex]

Hence,

[tex]2\frac{5}{6}=\frac{17}{6}[/tex]

Now with mixed numbers rewritten as improper fractions, we are ready to add

[tex]3\frac{7}{3}+2\frac{5}{6}=\frac{16}{3}+\frac{17}{6}[/tex]

rewriting 16/3 as 16/3 * 2/2 gives

[tex]\frac{16}{3}=\frac{32}{6}[/tex]

therefore, we have

[tex]\frac{16}{3}+\frac{17}{6}=\frac{32}{6}+\frac{17}{6}[/tex]

and now we just add the denominators to get

[tex]\frac{32}{6}+\frac{17}{6}=\frac{49}{6}[/tex]

Hence,

[tex]3\frac{7}{3}+2\frac{5}{6}=\frac{49}{6}[/tex]

which is our answer!