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find the equations of the line those pass through (2/3, -3/5) and have slope 5/3

Sagot :

Slope intercept form (general)

y = mx + b

Where:

m= slope

b= y-intercept

m = 5/3

y = 5/3x + b

Replace ( x,y ) by the given point (2/3,-3/5) and solve for b.

-3/5 = 5/3 (2/3) + b

-3/5 = 10/9 + b

-3/5 - 10/9 = b

b = -77/45

y = 5/3x - 77/45

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