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Sagot :
We have to use the equation
[tex]d=rt[/tex]Where r = 12 mph, d = 20 miles, let's find t.
[tex]\begin{gathered} 20=12t \\ t=\frac{20}{12}=\frac{10}{6}=\frac{5}{3} \end{gathered}[/tex]She'll take 5/3 hours to get there which is equivalent to 1 2/3 hours.
Let's transform 2/3 hours to minutes to find the exact time she has to leave.
We know that 1 hour is 60 minutes.
[tex]\frac{2}{3}hr\cdot\frac{60\min}{1hr}=\frac{120}{3}\min =40\min [/tex]So, she will take exactly 1 hour and 40 minutes.
If you have to get there at 10:00 A.M., then she has to leave at 8:20 A.M.
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