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I'm having trouble finding the length of NP and MN, thinking it has something to do with tan, cos, and sin, but not completely sure.

Im Having Trouble Finding The Length Of NP And MN Thinking It Has Something To Do With Tan Cos And Sin But Not Completely Sure class=

Sagot :

Bisects: to divide into two equal parts.

In this case, DB is bisecting the ∠ABC, then the ∠ABD

As OP is bisecting ∠MON, that means that ∠NOP and ∠POM have the same measure.

Then:

[tex]m\angle MON=m\angle NOP+m\angle POM[/tex]

As ∠NOP = ∠POM, we get:

[tex]m\angle MON=m\angle NOP+m\angle NOP=2\cdot m\angle NOP[/tex]

Replacing the value we get:

[tex]m\angle MON=2\cdot20=40[/tex]

Based on this, we can use the trigonometric functions, as we have an angle and one side. Specifically, the tangent function:

[tex]\tan \alpha=\frac{opposite}{\text{adyacent}}[/tex]

First, to calculate NP, we get the following:

[tex]\tan 20=\frac{NP}{6}[/tex]

Isolating for NP:

[tex]NP=6\cdot\tan 20[/tex][tex]NP=2.18[/tex]

Then, calculating for MN we get the following:

[tex]\tan 40=\frac{MN}{6}[/tex]

Isolating for MN:

[tex]MN=6\cdot\tan 40[/tex][tex]MN=5.03[/tex]

Answer:

• NP = 2.18

,

• MN = 5.03