Answered

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For questions 8 - 10, find all the solutions for x.8. 2x 4+14= 229. 8x +19 -54 +3x?10. 7x² + 12 =51- 4x?

For Questions 8 10 Find All The Solutions For X8 2x 414 229 8x 19 54 3x10 7x 12 51 4x class=

Sagot :

x = 2 or x = -2

Explanation:

8) 2x² + 14 = 22

collect like terms by subtracting14 from both sides of the equation:

2x² + 14 - 14 = 22 - 14

2x² + 0 = 8

2x² = 8

DIvide both sides by 2:

2x²/2 = 8/2

x² = 4

Square root both sides of the equation:

[tex]\begin{gathered} \sqrt[]{x^2}\text{ = }\pm\sqrt[]{4} \\ x\text{ =}\pm2 \\ \pm2\text{ = +2 or -2} \\ x\text{ =2 or x = -2} \end{gathered}[/tex]

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