At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Alicia watched a drone take off from a bridge. The height of the drone (in meters above the ground)minutes after takeoff is modeled byh(t) = −3+^2 + 12t +96Alicia wants to know when the drone will land on the ground.1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number inthe equation.h(t) =2) How many minutes after takeoff does the drone land on the ground?

Sagot :

a.

Function:

[tex]h(t)=-3t^2+12t+96[/tex]

Factoring -3, we have:

[tex]\begin{gathered} h(t)=-3t^2+12t+96 \\ h(t)=-3(t^2-4t-32) \end{gathered}[/tex]

Middle term facotizing the term inside parenthesis:

[tex]\begin{gathered} h(t)=-3(t^2-4t-32) \\ h(t)=-3(t-8)(t+4) \end{gathered}[/tex]

This is the factored form.

b.

h(t) is the height.

When it lands on the ground, the height (h(t)) is 0, so we have:

[tex]\begin{gathered} h(t)=-3(t-8)(t+4) \\ 0=-3(t-8)(t+4) \end{gathered}[/tex]

If we solve this equation for t, we get the line drone lands on the ground.

Let's do this:

[tex]\begin{gathered} -3(t-8)(t+4)=0 \\ t=8,-4 \end{gathered}[/tex]

Time can't be negative, so the solution is t = 8 seconds.