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-15-3r=6r+3c Solve for r.

Sagot :

Answer:

[tex]r=\frac{-c-5}{3}[/tex]

Explanation:

We want to solve for r in the equation below;

[tex]-15-3r=6r+3c[/tex]

We need to move all terms of r to one side and divide both sides by the coefficient of r.

firstly subtract 6r from both sides;

[tex]\begin{gathered} -15-3r-6r=6r-6r+3c \\ -15-9r=3c \end{gathered}[/tex]

then add 15 to both sides;

[tex]\begin{gathered} -15+15-9r=3c+15 \\ -9r=3(c+5) \end{gathered}[/tex]

divide both sides by -9;

[tex]\begin{gathered} \frac{-9r}{-9}=\frac{3(c+5)}{-9} \\ r=\frac{-(c+5)}{3} \\ r=\frac{-c-5}{3} \end{gathered}[/tex]

Therefore;

[tex]r=\frac{-c-5}{3}[/tex]

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