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A gas has a temperature of 34.9 degrees C and a volume of 70.0 L. If the temperature increases to 86.8 degreesC , what is its final volume ?

Sagot :

Answer

Its final volume is 81.8 L

Explanation

Given;

Initial temperature, T₁ = 34.9°C = (34.9 + 273.15 K) = 308.05 K

Initial volume, V₁ = 70.0 L

Final temperature, T₂ = 86.8°C = ( 86.8 + 273.15 K) = 359.95 K

What to find:

The final volume at 86.8°C.

Step-by-step solution:

The final volume, V₂ can be calculated using Charle's law formula below:

[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow V_2=\frac{V_1T_2}{T_1} \end{gathered}[/tex]

Putting the values of the given parameters into the formula, we have

[tex]V_2=\frac{70.0L\times359.95K}{308.05K}=81.8\text{ }L[/tex]

Hence, if the temperature of the gas increases to 86.8 degrees C, its final volume is 81.8 L