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pls help meHow many liters of NH3 are needed to react completely with 30.0 L of NO (at STP)?4NH3 (g)+ 6NO(g) 5N2(g)+ 6H2o(g)a.5.0 Lc.7.5 Lb.20.0 Ld.120.0 L

Sagot :

Answer:

[tex]20.0\text{ L}[/tex]

Explanation:

Here, we want to get the volume of NH3 that will react with 30L of NO at STP

From the question, we have it that 4 moles of ammonia reacted 6 moles of NO

Thus, we have the mole ratio as 6 to 4

Thus, the volume of ammonia reacted would be:

[tex]\frac{4}{6}\times30\text{ = 20.0 L}[/tex]

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