Answer:
[tex]\text{Yes, If no more than a total of }\frac{1}{12}foot\text{ is needed for spacing between desks}[/tex]
Explanation:
Given that six office desks that are 7 1/12 feet long are to be placed together.
The length of the six desks is;
[tex]\begin{gathered} 6\times7\frac{1}{12} \\ =6\times7+6\times\frac{1}{12} \\ =42\frac{6}{12} \end{gathered}[/tex]
Given that the wall is 42 7/12 feet long.
Then the length of the six desks is shorter than the length of the wall.
[tex]42\frac{7}{12}-42\frac{6}{12}=\frac{1}{12}[/tex]
Therefore, it will fit on the wall if no more than a total of 1/12 foot is needed for spacing between desks.
[tex]\text{Yes, If no more than a total of }\frac{1}{12}foot\text{ is needed for spacing between desks}[/tex]