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11.Solve the given equation over the interval [0, 271): 2 sin x++3 = 0.117and x=64757X=- and x=332лx= -- and x=3T57x= -- and x=6and x3

Sagot :

Question:

Solution:

Let the following trigonometric equation:

[tex]2\sin (x)+\sqrt[]{3}=\text{ 0}[/tex]

Subtract the root of 3 from both sides of the equation:

[tex]2\sin (x)=-\sqrt[]{3}[/tex]

solve for sin(x):

[tex]\sin (x)=\text{ -}\frac{\sqrt[]{3}}{2}[/tex]

Applying the trigonometric circle on the given interval, we obtain that the correct answer is:

[tex]x\text{ = }\frac{4\pi}{3}\text{ , x = }\frac{5\pi}{3}[/tex]

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