Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

11.Solve the given equation over the interval [0, 271): 2 sin x++3 = 0.117and x=64757X=- and x=332лx= -- and x=3T57x= -- and x=6and x3

Sagot :

Question:

Solution:

Let the following trigonometric equation:

[tex]2\sin (x)+\sqrt[]{3}=\text{ 0}[/tex]

Subtract the root of 3 from both sides of the equation:

[tex]2\sin (x)=-\sqrt[]{3}[/tex]

solve for sin(x):

[tex]\sin (x)=\text{ -}\frac{\sqrt[]{3}}{2}[/tex]

Applying the trigonometric circle on the given interval, we obtain that the correct answer is:

[tex]x\text{ = }\frac{4\pi}{3}\text{ , x = }\frac{5\pi}{3}[/tex]

View image JaydrienI614632
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.