Answered

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I will show you the question

Sagot :

The given system is

[tex]\begin{cases}3x+6y=12 \\ x+2y=4\end{cases}[/tex]

First, we multiply the second equation by -3.

[tex]\begin{cases}3x+6y=12 \\ -3x-6y=-12\end{cases}[/tex]

Then, we combine the equations

[tex]\begin{gathered} 3x-3x+6y-6y=12-12 \\ 0=0 \end{gathered}[/tex]

This means the system has infinitely many solutions.

Hence, the answer is D.

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