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Sagot :
The given system is
[tex]\begin{cases}3x+6y=12 \\ x+2y=4\end{cases}[/tex]First, we multiply the second equation by -3.
[tex]\begin{cases}3x+6y=12 \\ -3x-6y=-12\end{cases}[/tex]Then, we combine the equations
[tex]\begin{gathered} 3x-3x+6y-6y=12-12 \\ 0=0 \end{gathered}[/tex]This means the system has infinitely many solutions.
Hence, the answer is D.
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