Answered

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How many pounds of candy that sells for $0.85 per Ib must be mixed with candy that sells for $1.22 per lb to obtain 9 lb of a mixture that should sell for $0.92 per lb? 50.85-per-lb candy: 73 lb (Type an integer or decimal rounded to two decimal places as needed.) $1.22-per-b candy

Sagot :

This system gives two equations

[tex]\frac{0.85x+1.22y}{9}=0.92[/tex][tex]x+y=9[/tex]

where x is the number pounds of $0.85/lb candy and y is the number of pounds of $1.22/lb candy.

The solution to the system is

[tex]x=7.297[/tex][tex]y=1.70[/tex]

Hence, 7.297 lb of $0.85 candy is required in order that if we mix them with 1.70 lb of $1.22 candy, we will get a 9 lb solution of 0.92 /lb candy.

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