Answered

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Solve the quadratic equations in questions 1 – 5 by factoring.1. x2 – 49 = 02. 3x3 – 12x = 03. 12x2 + 14x + 12 = 184. –x3 + 22x2 – 121x = 05. x2 – 4x = 5

Solve The Quadratic Equations In Questions 1 5 By Factoring1 X2 49 02 3x3 12x 03 12x2 14x 12 184 X3 22x2 121x 05 X2 4x 5 class=

Sagot :

Given:

There are given the equation:

[tex]-x^3+22x^2-121x=0[/tex]

Explanation:

According to the question:

We need to find the value of x by using the factoring:

S0,

From the equation:

[tex]-x^{3}+22x^{2}-121x=0[/tex]

Tthen,

[tex]\begin{gathered} -x^{3}+22x^{2}-121x=0 \\ -x(x^2-22x+121)=0 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} -x(x^2-22x+121)=0 \\ x(x-11)^2=0 \\ x=0; \\ x-11=0 \\ x=11 \end{gathered}[/tex]

Final answer:

Hence, the value of x by using factor method is shown below:

[tex]x=0,11[/tex]

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