Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A flashlight bulb uses 190.1W of power when the current in the bulb is 0.64 A. What is the voltage?

Sagot :

Given:

[tex]\begin{gathered} P=190.1\text{ W} \\ I=0.64\text{ A} \end{gathered}[/tex]

The power is given as,

[tex]P=VI[/tex]

Here, P is the power, V is voltage and I is the current.

Rearranging equation in order to get voltage,

[tex]V=\frac{P}{I}[/tex]

Putting all known values,

[tex]\begin{gathered} V=\frac{190.1\text{ W}}{0.64\text{ A}} \\ =297.03\text{ V} \end{gathered}[/tex]

Therefore, the voltage is 297.03 V.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.