Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Heart Rates For a certain group of individuals, the average heart rate is 74 beats per minute. Assume the variable is normally distributed and the standarddeviation is 2 beats per minute. If a subject is selected at random, find the probability that the person has the following heart rate. Use a graphing calculator.Round the answers to four decimal places.Higher than 73 beats per minute,P (x> 73) =

Sagot :

we need to determine P (x> 73)

when

mean: μ = 74 beats/min

standard deviation: σ = 2 beats/min

First we need to use the following formula:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

where

x = 73

μ = 74

σ = 2

and

Z is the z-score

... therefore

[tex]z=\frac{73-74}{2}=-\frac{1}{2}=-0.5[/tex]

If we check a table of z scores, we will find that when z = -0.5, then P = 0.3085

Now, since we need P(x>73)

therefore

[tex]P=1-0.3085=0.6915[/tex]

P(x>73) = 0.6915

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.